0.16x^2+0.72x=0

Solution for 0.16x^2+0.72x=0 equation:

0.16x^2+0.72x=0

a = 0.16; b = 0.72; c = 0;
Δ = b2-4ac
Δ = 0.722-4·0.16·0
Δ = 0.5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.72)-\sqrt{0.5184}}{2*0.16}=\frac{-0.72-\sqrt{0.5184}}{0.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.72)+\sqrt{0.5184}}{2*0.16}=\frac{-0.72+\sqrt{0.5184}}{0.32}
$